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The Extreme Values of the Fairness Parameter

Lax117284.ExtremeFairness · concepts/Lax117284/ExtremeFairness.lean · lax-117284

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    Natural Language Statement

    Lemma

    Three values of the fairness parameter are settled by inspection. For k=0k = 0 nothing is required of a schedule, so every instance is a yes-instance. For k=mk = m every client must be served on every day, which is possible exactly when no two jobs of a day conflict. For k>mk > m no client can be served often enough, so an instance with at least one client is a no-instance.

    Concept map
    2 concepts
    100%
    Proven claimDefinitionThis conceptRelated conceptA → B: B builds on A
    Evidence

    This concept declares 3 statements. Each proof establishes one of them relative to its assumptions.

    3 not_hasKFairSchedule_of_days_lt proven

    Lean source view on GitHub

    1import Lax117284.Scheduling
    2
    3/-!
    4---
    5title: The Extreme Values of the Fairness Parameter
    6type: lemma
    7---
    8Three values of the fairness parameter are settled by inspection. For k=0k = 0 nothing is
    9required of a schedule, so every instance is a yes-instance. For k=mk = m every client must
    10be served on every day, which is possible exactly when no two jobs of a day conflict. For
    11k>mk > m no client can be served often enough, so an instance with at least one client is a
    12no-instance.
    13
    14# Formalization Notes
    15
    16The case k>mk > m needs an instance with a client: an instance with none has nothing to
    17require and admits the empty schedule for every parameter.
    18-/
    19
    20namespace Lax117284.ExtremeFairness
    21
    22open Lax117284.Scheduling
    23
    24/-- **A fairness parameter of `0` requires nothing.** -/
    25axiom hasKFairSchedule_zero (I : Instance) : I.HasKFairSchedule 0
    26
    27/-- **Serving every client on every day is possible exactly for conflict-free
    28instances.** -/
    29axiom hasKFairSchedule_days_iff (I : Instance) :
    30 I.HasKFairSchedule I.days ↔ I.ConflictFree
    31
    32/-- **A fairness parameter above the number of days is unattainable**, as soon as there is
    33a client of whom it is demanded. -/
    34axiom not_hasKFairSchedule_of_days_lt {I : Instance} {k : ℕ} (hk : I.days < k)
    35 (hn : 0 < I.clients) : ¬ I.HasKFairSchedule k
    36
    37end Lax117284.ExtremeFairness
    38
    Show ProofShow ProofShow Proof
    Formalization Notes

    The case k>mk > m needs an instance with a client: an instance with none has nothing to require and admits the empty schedule for every parameter.

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