Proof of `Duplicating a matched prediction under all-pairs accumulation` (1st statement)

groundedproofs/Lax303562Proofs/Duplication.lean · lax-303562

What this proof establishes

no assumptions

Assuming the claims on the left, the claim on the right holds — checked by the archive's pipeline. Proof code is not displayed here.

Read the Lean proof on GitHub

Description

Clearing the two positive denominators turns the comparison of quotients into s(D+1)<(s+v)Ds · (D + 1) < (s + v) · D, i.e. s<vDs < v · D, which is s/D<vs / D < v.