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First-order logic cannot count: games on bare sets

Lax945089.GamesOnSets · concepts/Lax945089/GamesOnSets.lean · lax-945089

proven

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    Natural Language Statement

    Theorem

    Two finite sets with at least nn elements each, as structures over the empty vocabulary, are nn-round equivalent: the duplicator answers a new element by a new element and an old one by its match. Hence an order-free first-order definable property of bare sets is constant on the sets beyond some size: first-order logic counts up to its quantifier depth and no further.

    Concept map
    27 concepts
    100%
    Proven claimDefinitionThis conceptRelated conceptA → B: B builds on A
    Evidence

    This concept declares 2 statements. Each proof establishes one of them relative to its assumptions.

    1 efEquiv_bare proven

    2 exists_card_bound_of_foDefinableFree proven

    Lean source view on GitHub

    1import Mathlib.ModelTheory.Order
    2import Mathlib.Order.Defs.LinearOrder
    3import Lax904597.Problems
    4import Lax904597.Interpretations
    5import Lax904597.Relativized
    6import Lax904597.SecondOrder
    7import Lax904597.Classes
    8import Lax485149.Problems
    9import Lax485149.FirstOrderDefinability
    10import Lax485149.TransitiveClosure
    11import Lax485149.DeterministicTransitiveClosure
    12import Lax485149.ClassNL
    13import Lax485149.ClassL
    14import Lax535992.InflationaryFixedPoint
    15import Lax535992.ClassPTIME
    16import Lax134656.PartialFixedPoint
    17import Lax895169.ArithmeticLogic
    18import Lax945089.OrderFreeFirstOrder
    19import Lax945089.EhrenfeuchtGames
    20import Lax945089.PebbleGames
    21import Lax945089.Even
    22import Lax945089.Parity
    23import Lax945089.TransitiveClosureReductions
    24
    25/-!
    26---
    27title: First-order logic cannot count: games on bare sets
    28type: theorem
    29---
    30Two finite sets with at least nn elements each, as structures over the
    31empty vocabulary, are nn-round equivalent: the duplicator answers a new
    32element by a new element and an old one by its match. Hence an order-free
    33first-order definable property of bare sets is constant on the sets beyond
    34some size: first-order logic counts up to its quantifier depth and no
    35further.
    36-/
    37
    38namespace Lax945089.GamesOnSets
    39
    40open FirstOrder FirstOrder.Language
    41open Lax904597.Problems Lax904597.Interpretations Lax904597.Relativized Lax904597.SecondOrder
    42open Lax904597.Classes
    43open Lax485149.Problems Lax485149.FirstOrderDefinability Lax485149.TransitiveClosure
    44open Lax485149.DeterministicTransitiveClosure Lax485149.ClassNL Lax485149.ClassL
    45open Lax535992.InflationaryFixedPoint Lax535992.ClassPTIME
    46open Lax134656.PartialFixedPoint Lax895169.ArithmeticLogic
    47open Lax945089.OrderFreeFirstOrder Lax945089.EhrenfeuchtGames Lax945089.PebbleGames
    48open Lax945089.Even Lax945089.Parity
    49open Lax945089.TransitiveClosureReductions
    50
    51/-- Two sets with at least `n` elements are `n`-round equivalent. -/
    52axiom efEquiv_bare :
    53 ∀ {M N : Type} [Language.empty.Structure M] [Language.empty.Structure N] [Finite M] [Finite N]
    54 (n : ℕ),
    55 n ≤ Nat.card M → n ≤ Nat.card N → EFEquiv Language.empty M N n
    56
    57/-- An order-free first-order property of bare sets is eventually constant. -/
    58axiom exists_card_bound_of_foDefinableFree :
    59 ∀ {P : DecisionProblem Language.empty}, FODefinableFree P →
    60 ∃ N : ℕ, ∀ (A B : Type) [Language.empty.Structure A] [Language.empty.Structure B] [Finite A]
    61 [Finite B]
    62 [Nonempty A] [Nonempty B], N ≤ Nat.card A → N ≤ Nat.card B → (P A ↔ P B)
    63
    64end Lax945089.GamesOnSets
    65
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