Proof of `Taking induced subgraphs and left lexicographic products` (2nd statement)
What this proof establishes
no assumptions
Assuming the claims on the left, the claim on the right holds — checked by the archive's pipeline. Proof code is not displayed here.
Description
, (1) ⇒ (2). In the formula for the factor depending on counts homomorphisms out of a disjoint union of subgraphs of induced by the classes of a partition. Each of those induced subgraphs lies in , so none of them distinguishes from , and the counts agree summand by summand.