Proof of `Taking summands and preservation under disjoint unions` (1st statement)
What this proof establishes
no assumptions
Assuming the claims on the left, the claim on the right holds — checked by the archive's pipeline. Proof code is not displayed here.
Description
, (2) ⇔ (3). Forwards, the same decomposition applied with exhibits a linear combination determined by whose coefficients are positive; after grouping the summands by isomorphism type the lemma on determined linear combinations places every sub-union in . Backwards, (1) ⇒ (2) applied to suffices, since and are the same relation.