Proof of `A determined linear combination determines its constituents`
What this proof establishes
no assumptions
Assuming the claims on the left, the claim on the right holds — checked by the archive's pipeline. Proof code is not displayed here.
Description
A determined linear combination determines its constituents. Enlarge the family to a family of representatives of all graphs on at most vertices, being the bound on the sizes of the members, and extend the coefficients by zero. Multiplying the hypothesis by for each — legitimate because is preserved under categorical products — turns it into the statement that a single vector meets the homomorphism matrix of in the same way for the two graphs. That matrix is invertible, so the vectors agree coordinatewise, and dividing by the nonzero coefficient gives the claim.