Lax314295.FOIffAperiodic
First-order definable languages are exactly the aperiodic ones
concepts/Lax314295/FOIffAperiodic.lean · lax-314295
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Evidence
Each proof establishes this claim relative to its assumptions.
In the paper
- page 130 of the paper of lax-157538, Transducers
Theorem
A language is definable in first-order logic if and only if it is recognised by an aperiodic deterministic automaton (Theorem C.4.11 of Transducers, Schützenberger, McNaughton and Papert). The two implications are the separate statements and ; this statement is their conjunction.
Lean source view on GitHub
| 1 | import Lax765601.StateTransformations |
| 2 | import Lax314295.MSOLogic |
| 3 | |
| 4 | /-! |
| 5 | --- |
| 6 | title: First-order definable languages are exactly the aperiodic ones |
| 7 | type: theorem |
| 8 | --- |
| 9 | A language is definable in first-order logic if and only if it is recognised |
| 10 | by an aperiodic deterministic automaton (Theorem C.4.11 of *Transducers*, |
| 11 | Schützenberger, McNaughton and Papert). The two implications are the separate |
| 12 | statements `AperiodicOfFO` and `FOOfAperiodic`; this statement is their |
| 13 | conjunction. |
| 14 | |
| 15 | # Formalization notes |
| 16 | |
| 17 | The alphabet is assumed finite. |
| 18 | -/ |
| 19 | |
| 20 | namespace Lax314295.FOIffAperiodic |
| 21 | |
| 22 | open Lax765601.StateTransformations Lax314295.MSOLogic |
| 23 | |
| 24 | /-- A language is first-order definable if and only if some aperiodic dfa |
| 25 | recognises it. -/ |
| 26 | axiom foDefinable_iff_aperiodic_dfa {A : Type} [Finite A] (L : Language A) : |
| 27 | FODefinable L ↔ |
| 28 | ∃ (σ : Type) (_ : Finite σ) (M : DFA A σ), TransAperiodic M.step ∧ M.accepts = L |
| 29 | |
| 30 | end Lax314295.FOIffAperiodic |
| 31 |
Formalization notes
The alphabet is assumed finite.
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