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Evidence
Each proof establishes this claim relative to its assumptions.
Theorem
Every bottom-up tree automaton with finitely many states has an equivalent deterministic tree automaton with finitely many states over the same ranked alphabet.
Lean source view on GitHub
| 1 | import Lax53.RankedTree |
| 2 | import Lax53.TreeAutomaton |
| 3 | |
| 4 | /-! |
| 5 | --- |
| 6 | title: Determinization of tree automata |
| 7 | type: theorem |
| 8 | --- |
| 9 | |
| 10 | Every bottom-up tree automaton with finitely many states has an equivalent |
| 11 | deterministic tree automaton with finitely many states over the same ranked |
| 12 | alphabet. |
| 13 | -/ |
| 14 | |
| 15 | namespace Lax53.Determinization |
| 16 | |
| 17 | open Lax53.RankedTree |
| 18 | open Lax53.TreeAutomaton |
| 19 | |
| 20 | universe u v |
| 21 | |
| 22 | axiom exists_deterministic_equivalent {A : RankedAlphabet.{u}} {Q : Type v} |
| 23 | [Fintype Q] (M : Automaton A Q) : |
| 24 | ∃ Q' : Type v, ∃ _ : Fintype Q', ∃ D : Automaton A Q', |
| 25 | D.Deterministic ∧ D.language = M.language |
| 26 | |
| 27 | end Lax53.Determinization |
| 28 |
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